If a power lifter raises a 1000N weight a distance of 2 meters in 0.5 seconds, what is his power out put?

P = 4000 [W]

Explanation:

In order to solve this problem, we must first determine the work, which is defined as the product of force by distance.

W = F*d

where:

W = work [J] (units in Joules)

F = force = 1000[N]

d = distance = 2 [m]

W = 1000*2

W = 2000 [J]

And power is defined as the relationship between work and the time in which the work is done.

P = W/t

P = power [W] (units of watts)

t = time = 0.5 [s]

P = 2000/0.5

P = 4000 [W]

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