a ball is rolling ar 4.80m/s over level ground when it encounters a ramp which gives it an acceleration of -0.875m/s^{2. if the ramp is 0.750m long, what is the final velocity of the ball when it reaches the top of the ramp?

4.66m/s

Explanation:

Given parameters:

Initial velocity  = 4.8m/s

Acceleration = -0875m/s²

Length of the ramp  = 0.75m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply the right motion equation;

     V² = U²  +  2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance  = length of ramp

   Insert the parameters;

      V²   = 4.8²  + 2(-0.875)0.75

      V²   = 23.04 - 1.31

      V²  = 21.73

      V = √21.73  = 4.66m/s

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