1. Calculate the specific heat capacity of the metal Use 4200 j/kg/°C for specific heat capacity of water
Heat gained by water = heat loss by the metal
M, XC X XT = M. XCX XT
M, X 4200 x 40-28 = 24.3 x cm x 99-40
M, X 4200 x 12 = 24.3 x x 59
M., 50,400 = 1.433.7C-I

Two resistors r1 and r2 may be connected either in series or parallel across an ideal battery with emf ε. we desire the rate of energy dissipation of the parallel combination to be 8.75 times that of the series combination. if r1 = 105 ω, what are the (a) smaller and (b) larger of the two values of r2 that result in that dissipation rate?