Physics, 11.11.2020 23:20 tatiiiee

The displacement-time graph below represents the motion of a chart initially moving forward along a straight line. During which interval is the cart moving forward at a constant speed AB

BC

CD

DE

The displacement-time graph below represents the motion of a chart initially moving forward along a

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Answer from: raconteuraki

The answer is CD because the line is straight. That means that it is not accelerating or decreasing. Therefore it is at a constant speed.

Answer from: amcalfie

The uniform motion ratios allow finding which intervals have constant velocity, the correct answers are

BC Positive velocity

CD Zero speed

DE Negative velocity

Kinematics studies the movement of bodies, establishing relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is called uniform movement

v = $\frac{\Delta_x}{\Delta t}$

Δx = v Δt

Where v is average velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.

This equation we see that the relationship between displacement and time is linear, let's analyze each interval given in the graph

AB interval

In this interval the graph shows a curve whereby the movement is accelerated

BC interval

In this interval the graph is a line with a positive slope, therefore the movement is uniform with positive velocity

CD interval

In this part we have a line of zero slope

In motion it is uniform with zero speed, that is, the car is stopped

DE interval

The graph of this section is a line with a negative slope, consequently the velocity is negative.

With this analysis we see that the only interval that the movement is accelerated is the AB interval

In conclusion, using the uniform motion relationships we can find that intervals have constant velocity, the correct answers are

BC Positive velocity

CD Zero speed

DE Negative velocity

Learn more about average speed here:

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Answer from: Quest

The purpose of a lab is to do your "expirements" the importance of the topic is so you can now what the story is about and the last one is because no one is me with my question ( what is 3 over 4 x - 9 = 27 maybe you can )

Answer from: Quest

Ohm's law tells you that i = v/r where v is equivalent voltage and r is equivalent resistance of the circuit
since all circuits have the same voltage, your question is really asking which circuit has the lowest total resistance, since the lower the resistance, the higher the current
circuit a has a resistance of 5 ohms; circuit c is in series so has a resistance of 10 ohms; circuit b is in parallel and therefore has a resistance of 2.5 ohms (review your notes on adding resistances in parallel and series); therefore b has the highest current

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