A car is traveling west for 12 s its speed is 36.12 m/s in the same direction find the total distance the car traveled

We are given:

constant speed of the car (u) = 36.12 m/s

time in question (t) = 12 seconds

Solving for the Distance and Displacement:

from the second equation of motion:

s = ut + 1/2 at^2

since we have 0 acceleration:

s = ut

replacing the variables

s = 36.12 * 12

s = 433.44 m

Since the car is travelling in a straight line towards the same direction, it's Distance will be equal to its Displacement

Hence, both the Displacement and Distance covered by the car is

433.44 m

but since Displacement also has a direction vector along with it,

the Displacement will be  433.44 m due west

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