1. A poorly tuned car accelerates from rest to a speed of 28 m/s in 20 s. (a) What is the average acceleration of the car? (b) How far does it travel in this time?

answer///scientific method;

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.