An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time? Use this formula to solve: x = xo + vo t + ½ a t 2

The object will travel 675 m during that time.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the path is a straight line, but the velocity is not necessarily constant because there is an acceleration.

In other words, a body performs a u.a.r.m when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases uniformly.

In this case, the position is calculated using the expression:

x = xo + vo*t + ½*a*t²

where:

x0 is the initial position. v0 is the initial velocity. a is the acceleration. t is the time interval in which the motion is studied.

In this case:

x0= 0v0= 0  because the object is initially stationarya= 6 t= 15 s

Replacing:

x= 0 + 0*15 s + ½*6 *(15s)²

Solving:

x=½*6 *(15s)²

x=½*6 *225 s²

x= 675 m

The object will travel 675 m during that time.

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Pe = 1/2k(x)^2  and .05n/m = .05x10^-9m = x