A bulldozer drags a 252 kg log along the rough horizontal ground. The cable attached to the log applies a 525 N force at an angle of 30.0° above the ground. The coefficient of kinetic friction between the log and the ground is 0.150. Assume the direction of motion is + x and upward is + y . 1.) What is the normal force acting on the log?
2.) What kinetic friction force is acting on the log? Include the proper sign.
3.) What is the acceleration of the log?