Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plates are spaced 1.4 mm apart and the voltage across them is changing at a rate of 110 V/s .

Solution:

The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :

Differentiating on both the sides with respect to time, we get

Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :

       V/m-s

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge