If a water balloon is launched with an initial velocity of 30.1 meters per second, at an angle of 24 degrees above horizontal, how much time will it take the balloon to reach the ground again? Please provide an explanation as well.

2.45 sec

Explanation:

use the equation:

a = (Vfy-Viy) / t a=-10m/sec sq

Viy = 30.1 Sin 24 = +12.24

Vfy = - Viy = -12.24

-10 = (-12.24-12.24)/t

t = 24.48/10= 2.45 sec

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explanation:

connect the batteries in series and hope