A circus performer swings down from a platform on a rope tied to the top of a tent in a pendulum-like swing. The performer's feet tough the ground 9 meters below where the rope is tied. how fast is the performer moving at the bottom of the arc?

First solve for time to fall using: = √2 ∶ 2(9) = 1.35. Then solve for velocity √9.8

2

2

using: = ∶ 9.8 2 ∗ 1.35 =13.23 m/s The performer’s velocity is 13.2 m/s

at the bottom of the swing.

Explanation:

that would be b i just took the test : )

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