A stone is thrown horizontally at 15 m/s from the top of a cliff 44 meters high. How far from the base does the stone hit the ground?

  44.9 m

Explanation:

For ballistic motion in x-y coordinates, an appropriate equation can be ...

  y(x) = -4.9(x·sec(α)/v)² +tan(α)x + h0

where α is the angle of launch from the horizontal, and v is the magnitude of the launch velocity.

Here, we have v = 15 m/s, and α = 0, so the equation reduces to ...

  y = -4.9/225x^2 +44

For y = 0, we can find x to be ...

  x^2 = (44×225/4.9) ≈ 2020.41

  x ≈ 44.949

The stone hits the ground about 44.9 meters from the base of the cliff.

inverse v=i*r

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