A 2.80 kg mass is dropped from a height of 4.50 m. Find its kinetic
energy (KE) when it is 3.00 m
above the ground. PLEASE HELP!!!

82.32 J

Explanation:

Given:

Mass,  

Initial height,  

Final height,  

As the mass is dropped, its initial velocity is 0 m/s.

So, initial kinetic energy is also 0 J.

Now, according to conservation of energy,

Increase in Kinetic energy is equal to the decrease in potential energy.

Here, Decrease in potential energy is given as,

Δ

Now, increase in kinetic energy is equal to the kinetic energy at height  as the initial kinetic is 0.

∴ Kinetic energy at height 1.50 m above ground is given as the decrease in potential energy.

So, Kinetic energy = Decrease in potential energy =  

Kinetic energy at height 1.50 m above ground is .

an obstruction

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this