A man is trying to push a 250 N dresser across his carpeted bedroom. He applies a force of 20 N and the carpet provides a frictional force of 8N. Which vectors represented in the diagram below will you need to consider and what will be the resulting net force?

The resultant force can be obtained by subtracting vector C from Vector A and the value of net force is 12 N. Hence, option (C) is correct.

Given data:

The weight of man is, W = 250 N.

The magnitude of applied force is, F = 20 N.

The magnitude of frictional force is, f = 8 N.

As per the given problem and the diagram let the applied force be denoted by vector A, Then,

Magnitude of Vector A = 20 N

And the frictional force be denoted by vector C. Then,

Magnitude of Vector C = 8 N

We know that the role of frictional force is to oppose the motion or to oppose the effect of applied force. Then the resultant force is given as,

Thus, we can conclude that the resultant force can be obtained by subtracting vector C from Vector A and the value of net force is 12 N. Hence, option (C) is correct.

Learn more about the resultant force here:

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The correct option is;

B. Subtract vectors A from C; = 12 N

Explanation:

The given parameters are;

The weight of the dresser = 250 N

The force applied by the man = 20 N = C

The frictional force provided by the carpet = 8 N = The component of the weight resisting motion = A

Therefore, the net force tending to put the dresser in motion, , is given as follows;

= The force applied by the man, C - The frictional force provided by the carpet which is the component of the weight resisting motion, A

= C - A = 20 N - 8 N = 12 N

= 12 N

The resulting net force, = 12 N.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.