Two spheres are both launched horizontally from a 10-m-high table. Sphere A is launched with an initial speed of 5.0 m/s. Sphere B is launched with an initial speed of 2.5 mis. a. What are the times for each sphere to hit the floor? b. What are the distances that each travels from the edge of the table?

(a) Both spheres are launched with 0 initial velocity in the vertical direction, so they both hit the ground at time t such that

10 m - 1/2 g t ² = 0

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Solve for t :

10 m = 1/2 g t ²

t ² = (20 m) / g

t ≈ 1.4 s

(b) Sphere A travels a horizontal distance of

(5.0 m/s) (1.4 s) ≈ 7.1 m

while sphere B travels a distance of

(2.5 m/s) (1.4 s) ≈ 3.6 m

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