A rocket is launched with a velocity of 30 m/s at 40° to the horizontal. How far will it travel horizontally? 0 3.01 m 0 90.54 m 120 m O 141.39 m

The horizontal distance traveled by the rocket is 90.46 m

Explanation:

Given;

initial velocity of the rocket, u = 30 m/s

angle of projection, θ = 40°

the horizontal distance traveled by the rocket = ?

The horizontal distance traveled by the rocket is given by the range of the projectile.

The range of the projectile is given as;

Therefore, the horizontal distance traveled by the rocket is 90.46 m

The closest answer in the given options is 90.54 m

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6