31. If you threw a baseball straight out at 45 m/s from a height of 1.5 meters (A) how long would it be in the air? B) How far out would the ball travel? (8 points)

A) t = 0.55 s

B) x = 24.8 m

Explanation:

A) We can find the time at which the ball will be in the air using the following equation:

Where:

is the final height= 0  

is the initial height= 1.5 m

is the component of the initial speed in the vertical direction = 0 m/s        

t: is the time =?      

g: is the gravity = 9.81 m/s²

By solving the above equation for t we have:

Hence, the ball will stay 0.55 seconds in the air.

B) We can find the distance traveled by the ball as follows:

Where:  

a: is the acceleration in the horizontal direction = 0  

is the final position =?  

is the initial position = 0      

is the component of the initial speed in the horizontal direction = 45 m/s                                                                                            

Therefore, the ball will travel 24.8 meters.

I hope it helps you!

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