Two 3.0 kg bodies, A and B, collide. The velocities before the collision are and . After the collision, . What are (a) the x-component and (b) the y-component of the final velocity of B

The question seems incomplete the complete question is given below

Two 3 kg bodies, A and B, collide. The velocities before the collision are A = (32 i + 41 j) m/s and B = (31 i + 3.2 j) m/s. After the collision, velocity of A = (7.9i + 11 j) m/s. What are (a) the x-component and (b) the y-component of the final velocity of B

x- component (Vb)final = 55.1

y- component (Vb)final = 33.2

Explanation:

a) On applying law of conservation of momentum

initial momentum = final momentum

for x - component we take the coefficients of i from the given data

(Ma*Va)initial + (Mb*Vb)initial = (Ma*Va)final + (Mb*Vb)final

since Ma = Mb= 3

so it will cancel out in the equation

(Va)initial + (Vb)initial = (Va)final + (Vb)final

32 + 31 = 7.9 + (Vb)final

(Vb)final = 55.1

b) for the y-component we take the component of j from the data.

(Ma*Va)initial + (Mb*Vb)final = (Ma*Va)final + (Mb*Vb)final

41+3.2 = 11 + (Vb)final

(Vb)final = 33.2

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the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.