A baseball is the road and angle of 30° above the horizontal. The horizontal component of the baseballs initial velocity is 12 m/s. What is the magnitude of the balls initial velocity

The magnitude of the ball's initial velocity is approximately 13.468 meters per second.  

Explanation:

From Trigonometry we get that magnitude of the velocity is obtained from the following trigonometric relation:

(Eq. 1)

Where:

- Magnitude of the horizontal component of the baseball, measured in meters per second.

- Magnitude of the velocity of the baseball, measured in meters per second.

- Angle of baseball above the horizontal, measured in sexagesimal degrees.

Then, we clear the magnitude of the velocity of the baseball:

If we know that and , then the magnitude of the velocity of the baseball is:

The magnitude of the ball's initial velocity is approximately 13.468 meters per second.  

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

its c i just checked it