A rod on the surface of Jupiter's moon Callisto has a volume of 0.3 cubic meters [m3]. Determine the weight of the rod in units of pounds-force [lbf]. The specific gravity of the material is 4.7. Gravitational acceleration on Callisto is 1.25 meters per second squared [m/s2].

396.56 lbf

Explanation:

From the question given above, the following data were obtained:

Volume of rod = 0.3 m³

Specific gravity = 4.7

Gravitational acceleration (g) = 1.25 m/s²

Weight of rod =...?

Next, we shall determine the density of the rod. This can be obtained as follow:

Specific gravity = 4.7

Density of water = 1000 Kg/m³

Density of rod =...?

Specific gravity = Density of rod /Density of water

4.7 = Density of rod /1000

Cross multiply

Density of rod = 4.7 × 1000

Density of rod = 4700 Kg/m³

Next, we shall determine the mass of the rod. This can be obtained as follow:

Volume of rod = 0.3 m³

Density of rod = 4700 Kg/m³

Mass of rod =?

Density = mass /volume

4700 = Mass of rod / 0.3

Cross multiply

Mass of rod = 4700 × 0.3

Mass of rod = 1410 Kg

Next, we shall determine the weight of the rod. This can be obtained as follow:

Mass of rod = 1410 Kg

Gravitational acceleration (g) = 1.25 m/s²

Weight of rod =...?

Weight = mass × Gravitational acceleration

Weight of rod = 1410 × 1.25

Weight of rod = 1762.5 N

Finally, we shall convert 1762.5 N to pounds-force [lbf]. This can be obtained as follow:

1 N = 0.225 lbf

Therefore,

1762.5 N = 1762.5 N × 0.225 Lbf / 1 N

1762.5 N = 396.56 lbf

Therefore, the weight of the rod is 396.56 lbf