If the first stage provides a thrust of 5.31 mega-newtons [MN] and the space shuttle has a mass of 5,760,000 pound-mass [lbm], what is the acceleration of the spacecraft in miles per hour squared [mi/h2]?

The acceleration of the spacecraft is 16,367.62 miles/hr²

Explanation:

Given;

thrust of the spacecraft, F = 5.31 x 10⁶ N

mass of the spacecraft, m = 5,760,000 lbm = 2612692.051 kg

The acceleration of the spacecraft in m/s² is given by Newton's second law of motion;

F = ma

a = F / m

The acceleration in miles per hour square is given by;

Therefore, the acceleration of the spacecraft is 16,367.62 miles/hr²

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

a.   mass number from atomic number