Balance the following chemical reaction:
Na3P + CaF2 --> NaF +
+
Ca3P2

Let a, b, c, d be constants such that

a Na₃P + b CaF₂   →   c NaF + d Ca₃P₂

Count the atoms on either side.

Left:

Na = 3a, P = a, Ca = b, F = 2b

Right:

Na = c, F = c, Ca = 3d, P = 2d

To get the same number of atoms of each element on both sides, we would have

3a = c

a = 2d

b = 3d

2b = c

If we let d = 1, we get a = 2, b = 3, and c = 6, so the balanced equation is

2 Na₃P + 3 CaF₂   →   6 NaF + Ca₃P₂

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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explanation: