The school zone in front of your school has a posted speed limit of 25 mi/h, which is about 11 m/s. Let's examine the stopping of a car in several different situations. A.) The crossing guard holds up her stop sign, and the driver is paying attention well. The car moves at a constant rate of 11 m/s for 2.3 seconds while the driver reacts l, then slows down at a constant rate of -4.5 m/s^2. What is the stopping distance for the car in this situation?
B.) A child appears to be running into the street ahead. It takes 2.3 seconds for the driver to react and begin to brake, but this time at a rate of -7.5 m/s^2. What is the stopping distance for the car in this situation?
C.) The driver is looking at her phone and has a total reaction time of 4.6 seconds as the car is moving at a constant speed of 11 m/s. If the driver slams on her brakes and slows down at the rate of -8.2 m/s^2, what is the stopping distance for the car in this situation?

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank