A object spins through an angular displacement of 10 radians and has an angular acceleration of 2.3 rad/sec-squared. Assuming it began spinning from rest, over what time interval did the acceleration occur?

The acceleration of the object occurred at 2.95 s

Explanation:

Given;

initial angular velocity of the object, ω = 0

angular acceleration, α = 2.3 rad/s²

angular displacement of the object, θ = 10 radians

The time of the motion is given by the following kinematic equation;

θ = ω + ¹/₂αt²

θ = 0 + ¹/₂αt²

θ = ¹/₂αt²

Therefore, the acceleration of the object occurred at 2.95 s

2b2t

explanation:

2b2t

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.