The distance between pitcher and catcher on a baseball field is 18.4 m. If a pitcher releases a ball from a height of 1.5 m and the catcher catches the ball right at ground level, how fast did the pitcher throw the ball?

33.26 m/s

Explanation:

The initial velocity of the ball can be determined by;

R = v

Where R is the range (distance between pitcher and catcher), H is the height covered, v is the initial velocity and g is the acceleration due gravity (9.8 m/).

So that;

18.4 = v

      = v

      = v

     = 0.5533v

⇒ v =

      = 33.2550

The initial velocity of the ball is 33.26 m/s.This is the velocity with which the pitcher threw the ball.

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