A student throws a baseball upwards at an angle of 60 degrees to the horizontal. The initial horizontal and vertical components are 12.50 m/s and 21.70 m/s, respectively At position C, the ball will have a horizontal velocity of -

12.5 m/s

Explanation:

Given that,

The initial horizontal and vertical components are 12.50 m/s and 21.70 m/s, respectively.

We need to find the horizontal velocity of the ball at position C.

It is a case of projectile motion. We know that in case of projectile motion, the horizontal velocity of the projectile remains the same while vertical velocity varies. It can be very clear that the horizontal velocity at C is 12.5 m/s.

an obstruction

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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