14.4 K. L of heat is required to raise the temperature of a 12 kg substance from 275 K to 275.5 K. Identify the
substance

The substance is Ethanol

Explanation:

To solve this problem we must use the expression of thermal energy calculation that relates the mass of a body with the specific heat of this and the temperature difference.

Q = m*Cp*(T_f - T_i)

where:

Q = amount of heat = 14.4 [kJ]

m = mass = 12 [kg]

Cp = specific heat [kJ/kg*K]

T_f = final temperature = 275.5 [K]

T_i = initial temperature = 275 [K]

Therefore we need to calculate Cp, and then compare this with the values in the given table attached.

Cp = 14.4/(12*(275.5 - 275))

Cp = 2.4 [kJ/kg*K]

Now we compare the Cp with the values given in the table.

So the substance is Ethanol

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