Physics, 29.10.2020 16:30 gonzaleze18

Consider the four scenarios involving visible light. In scenario A, visible light has a wavelength of 715.3 nm. Determine its frequency, energy per photon, and color.

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The frequency is " $419.5\times 10^{12} \ s^{-1}$ ", energy per photon is " $2.780\times 10^{-19} \ J$ " and the color is "red".

Given:

Wavelength,

$\lambda = 715.1 \ nm$

or,

$= 715.1 \ nm\times (10^-9 \ m/nm)$

As we know the formula,

→ $Frequency = \frac{Speed \ of \ light}{wavelength}$

By substituting the values, we get

$= \frac{(3\times 10^8) }{715.1\times 10^{-9} }$

$= 419.5\times 10^{12} \ s^{-1}$

Now,

The energy per photon will be:

→ $E = Planck's \ constant\times Frequency$

$= 6.626\times 10^{-34}\times 419.5\times 10^{12}$

$= 2.780\times 10^{-19} \ J$

Thus the above answer is correct.

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Answer from: QueenElizabeth353

1. frequency (f) = 4.194 × 10^14Hz

2. Energy of photon (E) = 2.779 × 10^-19 J

3. Color is RED

Explanation:

1. Based on the information in this question, a visible light has a wavelength of 715.3 nm.

λ = v/f

Where; λ = wavelength (nm)

v = speed of light (3 × 10^8m/s)

f = frequency (Hz)

f = v/λ

f = 3 × 10^8/715.3 × 10^-9

f = 0.004194 × 10^(8+9)

f = 0.004194 × 10^17

f = 4.194 × 10^14Hz

2. Energy per photon is calculated thus;

E = hf

Where; E = energy of photon (J)

h = Planck's constant (6.626 × 10^-34 J/s)

f = frequency (Hz)

E = 6.626 × 10^-34 × 4.194 × 10^14

E = 27.789 × 10^(-34+14)

E = 27.789 × 10^-20

E = 2.779 × 10^-19 J

3. Based on the wavelength range of the visible spectrum, wavelength of 715.3nm falls between 625-740nm, which is RED color of light. Hence, the color of the visible light is RED.

Answer from: Quest

10 neutrons is the answer

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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