What is the net work, in joules, required to stop a crate of mass 64.5 kg that is moving at a speed of 1.26 m/s

51.2Joules

Explanation:

Work done = Force × distance

Force = mg = 64.5×9.81

Force = 632.745N

Next is to get the distance using the equation of motion

v² = u²+2gS

1.26² = 0+2(9.81)S

1.5876 = 19.62S

S = 1.5876/19.62

S = 0.0809m

Get the work done:

Work done = F×S

Work done = 632.745×0.0809

Work done = 51.2Joules

Hence the net work done in Joules is 51.2Joules

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

i think the answer would be b