What frequency of rotation, in rpm r p m , is required to give an acceleration of 1.4 g g to an astronaut's feet, if her feet are 1.3 m m from the platform's rotational axis

Complete question is;

Astronauts in the International Space Station must work out every day to counteract the effects of weightlessness. Researchers have investigated if riding a stationary bicycle while experiencing artificial gravity from a rotating platform gives any additional cardiovascular benefit.

What frequency of rotation, in rpm, is required to give an acceleration of 1.4 g to an astronaut's feet, if her feet are 1.3 m from the platform's rotational axis

ω = 31.035 rpm

Explanation:

The formula for the rotational speed is;

ω = √(α/r)

Where α is the rotational acceleration.

We are given;

Acceleration; α = 1.4g = 1.4 × 9.81 = 13.734 m/s²

radius; r = 1.3 m

Thus;

ω = √(13.734/1.3)

ω = 3.25 rad/s

We are told to get the frequency of rotation in rpm

Thus,

ω = 3.25 × 60/2π

ω = 31.035 rpm

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!