2.In a mass spectrograph, a singly charged ion is accelerated across a 2030 volt potential difference. It then enters a magnetic field of 0.500 Teslas. The radius of the obit was measured to be 12.0 cm. What is the mass of the ion

m = 1.42 × 10^(-25) kg

Explanation:

We are given;

Potential Difference; V = 2030 V

Magnetic field; B = 0.5 T

Radius; r = 12 cm = 0.12 m

Now, if the mass of the particle is m and the electron charge is q, and considering the fact that the magnetic field will provide a centripetal motion, then from magnetic field formula, force is;

F = mv²/r = qvB

Thus;

mv²r = qvB

v = qBr/m

Where v is velocity.

Now, the electrical energy will be equal to the kinetic energy.

Thus;

qV = ½mv²

Where V is potential difference

Thus;

v = √(2qV/m)

Thus, equating both v equations to get;

qBr/m = √(2qV/m)

Square both sides to get;

q²B²r²/m² = 2qV/m

Simplifying gives;

m = qB²r²/2V

q is charge of one electron and has a value of 1.6 × 10^(-19) C

Thus;

m = (1.6 × 10^(-19) × 0.5² × 0.12²)/(2 × 2030)

m = 1.42 × 10^(-25) kg

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: