A very bouncy ball is dropped from a height of 2.47 m to an asphalt playground surface and the height of its 5th bounce is measured to be 1.51 m. Find the coefficient of restitution of the ball for a collision with asphalt

the coefficient of restitution of the ball for a collision with asphalt=0.95

Explanation:

Initial height of the bounce from the ball, h  =2.47m

height of the 5th bounce of the ball , h₁= 1.51m

Making e the coefficient of the restitution, then the height covered by the ball after the 5th bounce is

h₁= e²ⁿh

Where n = 5

h₁= e²⁽⁵⁾h

e¹⁰=h₁/h

e¹⁰=1.51/2.47

e= (1.51/2.47)¹/¹⁰

e=0.95198≈ 0.95

Therefore, the coefficient of restitution of the ball for a collision with asphalt is 0.95

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .