A 0.150-kg baseball traveling in a horizontal direction with a speed of 21.0 m/s hits a bat and is popped straight up with a speed of 15.0 m/s. If the bat was in contact with the ball for 51.0 ms, what was the average force of the bat on the ball

17.65N

Explanation:

We know that the relationship for the impulse and momentum is given as

Ft=mv

given data

mass m=0.15kg

t= 51ms= 26.5/1000= 0.051seconds

velocity v1= 21m/s

Velocity v2=15m/s

substituting in the expression we have

Ft=m(v1-v2)

make F subject of formula we have

F=m(v1-v2) /t

F=0.15(21-15)/0.051

F=0.15*6/0.051

F=0.9/0.051

F=17.65N

dang that balls went far

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.