A vertical rope is attached to an object that has a mass of 40.0 kg and is at rest. The tension in the rope needed to give the object an upward speed of 3.50 m/s
in 0.700 s is

239.2 N

Explanation:

Given that a vertical rope is attached to an object that has a mass of 40.0 kg and is at rest.The tension in the rope needed to give the object an upward speed of 3.50 m/s

in 0.700 s is

The tension in the rope and the weight of the mass will be acting in an opposite direction.

T - mg = ma (1)

Where acceleration a = Velocity/ time

a = 3.5 / 0.7

a = 5 m/s^2

Substitutes acceleration a into the equation 1 above.

T - 40 × 9.8 = 40 × 5

T - 39.2 = 200

T = 200 + 39.2

T = 239.2N

Therefore, the tension in the rope needed to give the object an upward speed of 3.50 m/s

in 0.700 s is 239.2N

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts