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Aparticle's position is given by x = 3.00 - 9.00t + 3t2, in which x is in meters and t is in seconds. (a) what is its velocity at t = 1 s? (b) is it moving in the positive or negative direction of x just then? (c) what is its speed just then? (d) is the speed increasing or decreasing just then? (try answering the next two questions without further calculation.) (e) is there ever an instant when the velocity is zero? if so, give the time t; if not, answer "0". (f) is there a time after t = 3 s when the particle is moving in the negative direction of x? if so, give the time t; if not, answer "0".
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Physics, 23.06.2019 01:30
Energy transformations that involve one transformation from one type of energy to another are called transformations.
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Physics, 23.06.2019 02:20
3. a particle with initial velocity vâ 0=(5.85Ă103m/s)j^ enters a region of uniform electric and magnetic fields. the magnetic field in the region is bâ =â(1.35t)k^. you can ignore the weight of the particle. a. calculate the magnitude of the electric field in the region if the particle is to pass through undeflected, for a particle of charge +0.640 nc.
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