Connie had a bad night at her bowling league. When she gets home, she drops her bowling ball in disqust out the upstair window from a height of 3.65 m above the ground. Her husband saw the bowling ball from the downstair window when it was 1.7 m above the ground. How much time passes from the time when her husband sees Connie's bowling ball out his window to when it hits the ground? a .86 s b 2.17 s c .59 s d 4.73 s

Option C. 0.59 s

Explanation:

The following data were obtained from the question:

Height from which the ball was released = 3.65 m

Height from which the husband saw the ball = 1.7 m

Time taken (t) for the ball to get to the ground from the height where the husband saw the ball =?

The time taken (t) for the ball to get to the ground from the height where the husband saw the ball can be obtained as follow:

H = ½gt²

1.7 = ½ × 9.8 × t²

1.7 = 4.9 × t²

Divide both side by 4.9

t² = 1.7 / 4.9

Take the square root of both side

t = √(1.7 / 4.9)

t = 0.59 s

Therefore, the time taken (t) for the ball to get to the ground from the height where the husband saw the ball is 0.59 s

because if the tool that you are using is not balanced it there would be false mass.

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: