If the distance of an object is determined from the relation: d = a X + b Y Where: (d) is the distance covered by the body. (a)is a physical quantity which has a dimensions (L T^-1). (b)Is a physical quantity which has a dimensions (L T^-2). So: * The dimension formula of (X) is T and that of (Y) is T^2.

The dimension formula of (X) is T and that of (Y) is T^-2

The dimension formula of (X) is T^-1 and that of (Y) is T^2.

The dimension formula of (X) is T^-1 and that of (Y) is T^-2.

The dimension formula of X is T and that of Y is  T^2

Explanation:

                     d = aX + bY is ACTAULLY  

                     so v = LT^-1

                          t = T

                          numerics do not have any dimensional formula so ignore

                          a = LT^-2

                          t = T^2

                         So answer for x is T and y T^2

the answer is to check all of them! they all apply well at least i think so!

b mirrors submit a iisner? e. for which optical devices does d sometimes have a positive value? o a a and b o b. a and c o c. b and d 0 d. b and cb