Physics, 23.10.2020 15:20 blair23

Sirius is 22 times more luminous that the Sun, and Polaris is 2350 times more luminous that the Sun. Sirius appears 23 times brighter than Polaris. Polaris is times farther away than Sirius.

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Answer from: skywil8981

Polaris is approximately 4.796 times farther away than Sirius.

Explanation:

According to the inverse-square law, widely used in wave phenomena, the luminosity, a form of intensity of electromagnetic webs, is inversely proportional to the square of distance. In other words, we get the following definition:

$I \propto \frac{1}{r^{2}}$

$I = \frac{k}{r^{2}}$ (Eq. 1)

Where:

- Proportionality ratio, measured in watts.

- Distance from the center of the star, measured in meters.

- Luminosity of the star, measured in watts per square meter.

Then, we eliminate the proportionality ratio by constructing the following relationship:

$I_{S}\cdot r_{S}^{2} = I_{P}\cdot r_{P}^{2}$ (Eq. 2)

Where:

$I_{S}$ , $I_{P}$ - Intensities of Sirius and Polaris, measured in watts per square meter.

$r_{S}$ , $r_{P}$ - Distances from centers of Sirius and Polaris, measured in meters.

After some algebraic handling, we get that:

$\frac{r_{P}}{r_{S}} = \sqrt{\frac{I_{S}}{I_{P}} }$

If we know that $\frac{I_{S}}{I_{P}} = 23$ , then the distance ratio of Polaris to Sirius is:

$\frac{r_{P}}{r_{S}} =\sqrt{23}$

$\frac{r_{P}}{r_{S}} \approx 4.796$

In a nutshell, Polaris is approximately 4.796 times farther away than Sirius.

Answer from: Quest

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge, $v = \dfrac{e_p}{q}$ then the following gives us the potential difference, $\delta v = v_b - v_a$ $\begin{aligned} \delta v & = \dfrac{e_p_b}{q} - \dfrac{e_p_a}{q} \\ & = \dfrac{\delta e_p}{q} \end{aligned}$ the formula $\delta v = \delta e_p / q$ may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get $\delta e_p = q\delta v$ using q = 8.00 × 10⁻¹⁹ c and δv = 2.00 v, we get $\begin{aligned} \delta e_p & = (8.00\times10^{-19} \text{ c})(2.00\text{ v}) \\ & = 1.60\times 10^{-18}\text{ j} \end{aligned}$ the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Answer from: Quest

you'd use the equation that establishes a relationship between energy and wavelength, which looks like this

e=h⋅cλ, where

λ - the wavelength of the photon; c - the speed of light, usually given as 3⋅108m/s; h - planck's constant, equal to 6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m

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Sirius is 22 times more luminous that the Sun, and Polaris is 2350 times more luminous that the Sun....

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