icw 17a a 250 lb block is subjexted to a horizontal force p. the coefficient of friction between the block and surface is 0.2 determine the force P required to start moving the block up the incline

424.773N

Explanation:

Taking the sum of force along the incline. The forces acting along the incline is the moving force P and the frictional force Ff

P = mgsintheta

Ff = nR = nmgcostheta

n is the coefficient of friction

R is the normal reaction

m is the mass of the block

g is the acceleration due to gravity

Hence the force P required to start moving the block up the incline is 424.773N

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the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement