Use the principle of superposition (Equation 1.3) to predict the electric field at the point 0.5 meters to the right and 1.5 meters above the 5 nC charge. Express your result both in terms of x and y components, and then in terms of total magnitude and direction.

Explanation:

The x component of electric field Ex = k Q / R²

= 9 x 10⁹ x 5 x 10⁻⁹ / .5²

= 180 N .

The y component of electric field Ey = k Q / R²

The y component of electric field Ey

= 9 x 10⁹ x 5 x 10⁻⁹ / 1.5²

= 20 N

Total field =

= 181.1 N .

Angle with x axis = Tanθ = Ey / Ex = 20 / 180 = .111

= 6.33⁰

the answer would be c. motion and direction

i hope this : )