A 0.660 kg ball is dropped from rest from the top of a building and falls for 5.65 seconds. How tall was the building ?

The height of the building is approximately 156.58 m

Explanation:

The mass of the ball dropped from rest from the building top = 0.660 kg

The time in which the ball falls, t = 5.65 seconds

The height, h, of the building is given from the following equation of motion;

h = u·t + ¹/₂·g·t²

Where;

u = The initial velocity of the ball = 0 m/s

g = The acceleration due to gravity = 9.81 m/s²

Plugging in the values, we have;

h = 0 × 5.65 + ¹/₂ × 9.81 × 5.65² ≈ 156.58 m

The height of the building, h ≈ 156.58 m.

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