How far has a object fallen that is traveling 98 m/s In 10 seconds

The distance is, y = 489.5 [m/s]

Explanation:

To solve this problem we can use the following equation of kinematics.

where:

Vf = final velocity = 98 [m/s]

Vi = initial velocity = 0

g = gravity acceleration = 9.81 [m/s^2]

y = distance [m]

(98^2) = 0 + (2*9.81*y)

Note: the positive sign of the equation means that the acceleration of gravity acts in the direction of the movement of the object.

9604 = 19.62*y

y = 489.5 [m/s]

a) the event horizon, singularity, and the chute located between the two.