If mass A and B are both 2.5 kg, mass A is 1.0 m to the left of the fulcrum, mass B is 0.5 m to the right of the fulcrum, and the bar weighs 0.0 kg, what is the initial torque on the bar? a 4.46 Nm C.-4.46 Nm b. 12.26 Nm d. -12.26 Nm

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf,  ℰ,  to a battery's terminal voltage, v, current, i, and internal resistance, r, is    ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.

The relationship of both of them