Two skaters stand facing each other. One skater’s mass is 60 kg, and the other’s mass is 75 kg. The two skaters push off each other. After the push, the smaller skater has a velocity of 3.0 m/s. If no other forces are acting on the skaters, what is the velocity of the larger skater?

im guessing the west of station b

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

a. vertically

explanation:

i tried it and took the test

if im wrong then we have different tests