A race car traveling at 50 m/s is uniformly accelerated to a velocity of 25 m/s over a 10-second interval. A. What is the acceleration of the car?

B. What is its displacement during this time?

33: i think it’s b

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form