A long wire carrying a 5.5 A current perpendicular to the xy-plane intersects the x-axis at x=−2.0cm . A second, parallel wire carrying a 2.5 A current intersects the x-axis at x=+2.0cm . Part A At what point on the x-axis is the magnetic field zero if the two currents are in the same direction? Express your answer in centimeters. x x = nothing cm SubmitRequest Answer Part B At what point on the x-axis is the magnetic field zero if the two currents are in opposite directions? Express your answer in centimeters. x x = nothing cm SubmitRequest Answer Provide Feedback Next

a

The point on the x-axis where the magnetic field will be zero is  

b

The point on the x-axis where the magnetic field will be zero is Explanation:

From the question we are told that

   The first  current is

    The point of x- axis  intersection is  

    The second current is  

     The point of intersection of the x-axis is  

Generally given that the current of the two wires are same direction it means that the magnetic field in -between the wires will cancel out  giving zero

 So  

=>    

=>      

Here  d is the of one wire to the point where the magnetic field is 0

and  given that the total distance in-between the wire is  D  =  2 =  2 =  4

Hence the distance of the other wire to the point where magnetic field is zero is  (4 - d)

So

=>  

=>  

So the point on the x-axis where the magnetic field will be zero is  

 Generally given that the current of the two wires are opposition direction it means that the magnetic field at a position which is not in-between the wire will be zero  

Let that position be  k

Let  the distance from the middle of both wires to k  be Z  

So

=>  

=>    

=>    

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂