An 800 kg car exerts 4000N of applied force on a level road while being opposed by 700 N of friction. Determine the acceleration of the car.

a = 4.125 [m/s^2]

Explanation:

In order to calculate the value of acceleration, we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces [N]

m = mass [kg]

a = acceleration [m/s^2]

Performing a summation of forces on the x-axis, we have:

4000 - 700 = m*a

4000 - 700 = 800*a

a = 4.125 [m/s^2]

show the diagram then i will answer

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )