Determin the acceleration that results when an object starts at rest moves a distance and it’s final speed is 49 m/sec (show work please and equation used)
(also don’t understand this question at all)

The answer is below

Explanation:

The question is not complete since the distance is not given. But let us assume the object moves a distance of 100 m.

From newton's law for a moving body, we get the equation:

v² = u² + 2as

Where v is the final velocity of the object, u is the initial velocity of the object, s is the distance moved by the object and a is the acceleration of the object.

Given that the object is initially at rest, hence u = 0, final speed (v) = 49 m/s, distance (s) = ?

v² = u² + 2as

Substituting:

49² = 0² + 2as

2401 = 2as

a = 2401 / 2s

Substituting s = 100 m

a = 2401 / (2*100)

a = 12 m/s²

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.