11)A 1100 kg car travels on a straight highway with a speed of 30 m/s. The driver sees a red light ahead and applies her brakes, which exert a constant braking force of 4000N. In how many seconds will the car stop?

The time taken by the car to stop is 8.26 s.

Given data:

The mass of car is, m = 1100 kg.

The speed of car is, u = 30 m/s.

The magnitude of braking force is, F = 4000 N.

We need to first obtain the acceleration of car to get that, apply the Newton's second law as,

F = - ma    (Negative sign shows that the force will resist the motion)

4000 = -(1100) a

Now, apply the first kinematic equation of motion to obtain the time taken by the car to stop as,

v = u + at

Here, v is the final speed and v = 0, since car will stop finally.

So,

Thus , we can conclude that the time taken by the car to stop is 8.26 s.

Learn more about the Newton's second law of motion here:

link

Time taken = 8.25 second

Explanation:

Given:

Force = 4000 N

Force = ma

4,000 = (1100)(a)

Acceleration = 3.6363 m/s²

v = u + at

0 = 30 + (3.6363)t

Time taken = 8.25 second

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!