Calculate the electrostatic force between a negatively charged PVC pipe (m = 300 g, q = -0.0000007 C) and a positively charged sweater (m = 650 g, q = 0.0000009 C) when they are held 6 cm apart (the centers of their charges are 6 cm apart). Your answer should include the magnitude of the force and clearly state whether they would be pushing or pulling each other with that amount force.

1.575 N

Explanation:

Given that,

Charge on a PVC pipe, q₁ = -0.0000007 C

Charge on a positively charged sweater, q₂ = 0.0000009 C

Separation between charges, d = 6 cm = 0.06 m

We need to find the magnitude of the force between charges. The force between two charges is given by :

So, the electrostatic force has a magnitude of 1.575 N.

answer: its c lololo

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)